Jee Main
Logarithm
JEE Main 2021 (Online) 20th July Evening Shift
INTEGER+4 / -12021
The number of solutions of the equation
\({\log _{(x + 1)}}(2{x^2} + 7x + 5) + {\log _{(2x + 5)}}{(x + 1)^2} - 4 = 0\), x > 0, is :
\({\log _{(x + 1)}}(2{x^2} + 7x + 5) + {\log _{(2x + 5)}}{(x + 1)^2} - 4 = 0\), x > 0, is :