Jee Main
Limits Continuity And Differentiability
JEE Main 2021 (Online) 25th July Morning Shift
MCQ+4 / -12021
Let f : R \(\to\) R be defined as
\(f(x) = \left\{ {\matrix{ {{{\lambda \left| {{x^2} - 5x + 6} \right|} \over {\mu (5x - {x^2} - 6)}},} & {x < 2} \cr {{e^{{{\tan (x - 2)} \over {x - [x]}}}},} & {x > 2} \cr {\mu ,} & {x = 2} \cr } } \right.\)
where [x] is the greatest integer is than or equal to x. If f is continuous at x = 2, then \(\lambda\) + \(\mu\) is equal to :
\(f(x) = \left\{ {\matrix{ {{{\lambda \left| {{x^2} - 5x + 6} \right|} \over {\mu (5x - {x^2} - 6)}},} & {x < 2} \cr {{e^{{{\tan (x - 2)} \over {x - [x]}}}},} & {x > 2} \cr {\mu ,} & {x = 2} \cr } } \right.\)
where [x] is the greatest integer is than or equal to x. If f is continuous at x = 2, then \(\lambda\) + \(\mu\) is equal to :