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Definite Integration

JEE Main 2021 (Online) 1st September Evening Shift

MCQ+4 / -12021
Let f : R \(\to\) R be a continuous function. Then \(\mathop {\lim }\limits_{x \to {\pi \over 4}} {{{\pi \over 4}\int\limits_2^{{{\sec }^2}x} {f(x)\,dx} } \over {{x^2} - {{{\pi ^2}} \over {16}}}}\) is equal to :

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