Jee Main
Solutions
JEE Main 2021 (Online) 27th August Evening Shift
INTEGER+4 / -12021
40 g of glucose (Molar mass = 180) is mixed with 200 mL of water. The freezing point of solution is __________ K. (Nearest integer) [Given : Kf = 1.86 K kg mol\(-\)1; Density of water = 1.00 g cm\(-\)3; Freezing point of water = 273.15 K]
