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Electrochemistry

JEE Main 2021 (Online) 25th July Morning Shift

INTEGER+4 / -12021
Consider the cell at 25\(^\circ\)C

Zn | Zn2+ (aq), (1M) || Fe3+ (aq), Fe2+ (aq) | Pt(s)

The fraction of total iron present as Fe3+ ion at the cell potential of 1.500 V is x \(\times\) 10\(-\)2. The value of x is ______________. (Nearest integer)

(Given : \(E_{F{e^{3 + }}/F{e^{2 + }}}^0 = 0.77V\), \(E_{Z{n^{2 + }}/Zn}^0 = - 0.76V\))

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