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Chemical Kinetics And Nuclear Chemistry

JEE Main 2021 (Online) 27th August Evening Shift

INTEGER+4 / -12021
The first order rate constant for the decomposition of CaCO3 at 700 K is 6.36 \(\times\) 10\(-\)3s\(-\)1 and activation energy is 209 kJ mol\(-\)1. Its rate constant (in s\(-\)1) at 600 K is x \(\times\) 10\(-\)6. The value of x is ___________. (Nearest integer)

[Given R = 8.31 J K\(-\) mol\(-\)1; log 6.36 \(\times\) 10\(-\)3 = \(-\)2.19, 10\(-\)4.79 = 1.62 \(\times\) 10\(-\)5]

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