Jee Advanced
Statistics
JEE Advanced 2025 Paper 1 Online
MCQ+4 / -12025
Consider the following frequency distribution:
table {width: 100%;border-collapse: collapse;margin: 20px 0;} th {background-color: blue;color: white;border: 1px solid lightgrey;padding: 10px;} td {border: 1px solid lightgrey;padding: 10px;text-align: left;}| Value | 4 | 5 | 8 | 9 | 6 | 12 | 11 |
|---|---|---|---|---|---|---|---|
| Frequency | 5 | $f_1$ | $f_2$ | 2 | 1 | 1 | 3 |
Suppose that the sum of the frequencies is 19 and the median of this frequency distribution is 6.
For the given frequency distribution, let $\alpha$ denote the mean deviation about the mean, $\beta$ denote the mean deviation about the median, and $\sigma^2$ denote the variance.
Match each entry in List-I to the correct entry in List-II and choose the correct option.
| List – I | List – II |
|---|---|
| (P) 7 f1 + 9 f2 is equal to | (1) 146 |
| (Q) 19 α is equal to | (2) 47 |
| (R) 19 β is equal to | (3) 48 |
| (S) 19 σ2 is equal to | (4) 145 |
| (5) 55 |
