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Jee Advanced

Statistics

JEE Advanced 2025 Paper 1 Online

MCQ+4 / -12025

Consider the following frequency distribution:

table {width: 100%;border-collapse: collapse;margin: 20px 0;} th {background-color: blue;color: white;border: 1px solid lightgrey;padding: 10px;} td {border: 1px solid lightgrey;padding: 10px;text-align: left;}
Value458961211
Frequency5$f_1$$f_2$2113

Suppose that the sum of the frequencies is 19 and the median of this frequency distribution is 6.

For the given frequency distribution, let $\alpha$ denote the mean deviation about the mean, $\beta$ denote the mean deviation about the median, and $\sigma^2$ denote the variance.

Match each entry in List-I to the correct entry in List-II and choose the correct option.


























List – I List – II
(P) 7 f1 + 9 f2 is equal to (1) 146
(Q) 19 α is equal to (2) 47
(R) 19 β is equal to (3) 48
(S) 19 σ2 is equal to (4) 145
(5) 55


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