Jee Advanced
Differential Equations
JEE Advanced 2025 Paper 2 Online
INTEGER+4 / -02025
Let $y(x)$ be the solution of the differential equation
\(x^2 \frac{d y}{d x}+x y=x^2+y^2, \quad x>\frac{1}{e}\)
satisfying $y(1)=0$. Then the value of $2 \frac{(y(e))^2}{y\left(e^2\right)}$ is ____________.
