Jee Advanced
Trigonometric Functions And Equations
JEE Advanced 2024 Paper 1 Online
MCQ+3 / -12024
Let $\frac{\pi}{2} < x < \pi$ be such that $\cot x=\frac{-5}{\sqrt{11}}$. Then
\(\left(\sin \frac{11 x}{2}\right)(\sin 6 x-\cos 6 x)+\left(\cos \frac{11 x}{2}\right)(\sin 6 x+\cos 6 x)\)
is equal to :
