Jee Advanced
Coordination Compounds
JEE Advanced 2023 Paper 1 Online
MCQ+3 / -12023
Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option.
[Atomic Number: $\mathrm{Fe}=26, \mathrm{Mn}=25, \mathrm{Co}=27$ ]
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[Atomic Number: $\mathrm{Fe}=26, \mathrm{Mn}=25, \mathrm{Co}=27$ ]
.tg {border-collapse:collapse;border-spacing:0;width:100%}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;}
.tg .tg-1wig{font-weight:bold;text-align:left;vertical-align:top}
.tg .tg-0lax{text-align:left;vertical-align:top}
| List - I | List - II |
|---|---|
| (P) $t_{2 g}^6 e_g^0$ | (1) $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$ |
| (Q) $t_{2 g}^3 e_g^2$ | (2) $\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$ |
| (R) $\mathrm{e}^2 \mathrm{t}_2^3$ | (3) $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ |
| (S) $t_{2 g}^4 e_g^2$ | (4) $\left[\mathrm{FeCl}_4\right]^{-}$ |
| (5) $\left[\mathrm{CoCl}_4\right]^{2-}$ |
