Jee Advanced
Electrostatics
IIT-JEE 2009 Paper 1 Offline
Six point charges, each of the same magnitude q, are arranged in different manners as shown in Column II. In each case, a point M and a line PQ passing through M are shown. Let E be the electric field and V be the electric potential at M (potential at infinity is zero) due to the given charge distribution when it is at rest. Now, the whole system is set into rotation with a constant angular velocity about the line PQ. Let B be the magnetic field at M and \(\mu\) be the magnetic moment of the system in this condition. Assume each rotating charge to be equivalent to a steady current.
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| Column I | Column II | ||
|---|---|---|---|
| (A) | \(E=0\) | (P) | ![]() Charge are at the corners of a regular hexagon. M is at the centre of the hexagon. PQ is perpendicular to the plane of the hexagon. |
| (B) | \(V\ne 0\) | (Q) | ![]() Charges are on a line perpendicular to PQ at equal intervals. M is the midpoint between the two innermost charges. |
| (C) | \(B=0\) | (R) | ![]() Charges are placed on two coplanar insulating rings at equal intervals. M is the common centre of the rings. PQ is perpendicular to the plane of the rings. |
| (D) | \(\mu \ne 0\) | (S) | ![]() Charges are placed at the corners of a rectangle of sides a and 2a and at the mid points of the longer sides. M is at the centre of the rectangle. PQ is parallel to the longer sides. |
| (T) | ![]() Charges are placed on two coplanar, identical insulating rings are equal intervals. M is the midpoint between the centres of the rings. PQ is perpendicular to the line joining the centres and coplanar to the rings. |





