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Definite Integration

IAT (IISER) 2020

MCQ+4 / -12020

If $p(t)=\frac{t(t-1) \cdots(t-2019)}{2019!}$, then the value of


\(\int_0^1\left(\frac{1}{t+1}+\frac{1}{t+2}+\cdots+\frac{1}{t+2020}\right) p(-t-1) d t\)


is:

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