ComedkEllipseCOMEDK 2025 Morning ShiftMCQ+1 / -02025If the distance between the foci is equal to the length of the latus rectum, then the eccentricity of the ellipse isA $\frac{\sqrt{5}+1}{2}$B $\frac{1-\sqrt{5}}{2}$C $\frac{\sqrt{5}-1}{2}$D $\frac{1 \pm \sqrt{5}}{2}$Check AnswerClear SelectionReveal AnswerShow Explanation
