ComedkDifferential EquationsCOMEDK 2025 Morning ShiftMCQ+1 / -02025The solution of $(x+\log y) d y+y d x=0$ when $y(0)=1$ isA $y(x-1+\log y)+1=0$B $x y+y \log y+1=0$C $x y=y \log y-y-1$D $y(x+1+\log y)-1=0$Check AnswerClear SelectionReveal AnswerShow Explanation
