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Limits Continuity And Differentiability

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MCQ+1 / -02024

$$ \text { If } f(x)=\left\{\begin{array}{cc} \frac{1-\sin x}{(\pi-2 x)^2} & , \quad \text { if } x \neq \frac{\pi}{2} \\ \lambda, & \text { if } x=\frac{\pi}{2} \end{array}\right. $$


Then \(f(x)\) will be continues function at \(x=\frac{\pi}{2}\), then \(\lambda=\)

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