16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4e0,{"@context":"https://schema.org","@type":"Quiz","name":"Comedk 2023 Waves PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/comedk/questions/2023/physics/waves/jaoe38c1lpycov7i","educationalLevel":"Entrance exam preparation","about":"Comedk / Physics / Waves","hasPart":{"@type":"Question","name":"Comedk 2023 Waves PYQ with Solution","text":"A string vibrates with a frequency of 200 \\mathrm{~Hz}. When its length is doubled and tension is altered, it begins to vibrate with a frequency of 300 \\mathrm{~Hz}. The ratio of the new tension to the original tension is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"The frequency of a vibrating string can be expressed by the formula: f = \\frac{1}{2L} \\sqrt{\\frac{T}{\\mu}} Where: f is the frequency of the string, L is the length of the string, T is the tension in the string, and \\mu is the linear mass density of the string. Initially, the frequency of the string is 200 \\mathrm{~Hz} when the length is L and the tension is T_1. The formula becomes: 200 = \\frac{1}{2L} \\sqrt{\\frac{T_1}{\\mu}} When the length of the string is doubled to 2L and the tension is alter..."}}}18:T5e1,

The frequency of a vibrating string can be expressed by the formula:

$$ f = \frac{1}{2L} \sqrt{\frac{T}{\mu}} $$

Where:

$$f$$ is the frequency of the string,
$$L$$ is the length of the string,
$$T$$ is the tension in the string, and
$$\mu$$

Waves

Continue this paper

Similar Waves PYQs

More practice from this question