Electrochemistry

\(\mathrm{PbO}_{2(s)}\) is reduced.

\(\mathrm{PbSO}_{4(\mathrm{~s})}\) gets converted to \(\mathrm{Pb}_{(\mathrm{S})}\) and \(\mathrm{PbO}_{2(\mathrm{~s})}\)

\(\mathrm{SO}_3\) gas gets liberated and \(\mathrm{PbO}_{2(\mathrm{~s})}\) is formed.

\(\mathrm{Pb}_{(\mathrm{S})}\) gets consumed.