Comedk
Electrochemistry
COMEDK 2022
MCQ+1 / -02022
What will be the emf of the following cell at 25\(^\circ\)C?
Fe/Fe\(^{2+}\) (0.001 M) | | H\(^+\) (0.01 M) | H\(_2\)(g) (1 Bar) | Pt(s)
\(E_{(F{e^{2+}} /Fe)}^o = - 0.44\) V; \(E_{({H^ + }/{H_2})}^o = - 0.00\) V