ComedkIndefinite IntegrationCOMEDK 2021MCQ+1 / -02021\(\int {{{{2^x}} \over {\sqrt {1 - {4^x}} }}dx}\) is equal toA\((\log 2){\sin ^{ - 1}}{2^x} + C\)B\({1 \over 2}{\sin ^{ - 1}}{2^x} + C\)C\({1 \over {\log 2}}{\sin ^{ - 1}}{2^x} + C\)D\(2\log 2{\sin ^{ - 1}}{2^x} + C\)Check AnswerClear SelectionReveal AnswerShow Explanation
