ComedkDifferentiationCOMEDK 2020MCQ+1 / -02020If \({x^x} = {y^y}\), then \({{dy} \over {dx}}\) isA\(- {x \over y}\)B\(- {y \over x}\)C\({{1 + \log x} \over {1 + \log y}}\)D\(1 + \log \left( {{x \over y}} \right)\)Check AnswerClear SelectionReveal AnswerShow Explanation
