BitsatQuadratic EquationsBITSAT 2025MCQ+3 / -12025Roots of the equation $a x^2+b x+c=0(a, b, c>0)$ areABoth positiveBBoth negativeCOf opposite signDdepends on the values of $a, b$ and $c$Check AnswerClear SelectionReveal AnswerShow Explanation
