BitsatRotational MotionBITSAT 2024MCQ+3 / -12024The moment of inertia of a cube of mass $ m $ and side $ a $ about one of its edges is equal toA$ \frac{2}{3} m a^{2} $B$ \frac{4}{3} m a^{2} $C$ 3 m a^{2} $D$ \frac{8}{3} m a^{2} $Check AnswerClear SelectionReveal AnswerShow Explanation
