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Current Electricity

BITSAT 2024

MCQ+3 / -12024
In the given circuit, $ E_{1}=E_{2}=E_{3}=2 \mathrm{~V} $ and $ R_{1}=R_{2}=4 \Omega $, then current flowing through the branch $ A B $ is

BITSAT 2024 Physics - Current Electricity Question 1 English

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