16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T517,{"@context":"https://schema.org","@type":"Quiz","name":"Bitsat 2024 Sets And Relations PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/bitsat/questions/2024/mathematics/sets-and-relations/m7pung1a","educationalLevel":"Entrance exam preparation","about":"Bitsat / Mathematics / Sets And Relations","hasPart":{"@type":"Question","name":"Bitsat 2024 Sets And Relations PYQ with Solution","text":"In a statistical investigation of 1003 families of Calcutta, it was found that 63 families has neither a radio nor a TV, 794 families has a radio and 187 has TV. The number of families in that group having both a radio and a TV is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"In a survey of 1003 families in Calcutta, we have the following information: 63 families have neither a radio nor a TV. 794 families have a radio. 187 families have a TV. We need to calculate how many families have both a radio and a TV. Step-by-step Solution: Calculate the total number of families with either a radio or a TV. Using the formula for the complement set: n(R \\cup T) + n(R \\cup T)' = \\text{Total families} n(R \\cup T) + 63 = 1003 Solving for n(R \\cup T) : n(R \\cup T) = 1003 - 63 = 9..."}}}18:T42b,

In a survey of 1003 families in Calcutta, we have the following information:

63 families have neither a radio nor a TV.

794 families have a radio.

187 families have a TV.

We need to c

Sets And Relations

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