BitsatMatrices And DeterminantsBITSAT 2024MCQ+3 / -12024If $ A=\frac{1}{3}\left[\begin{array}{ccc}1 & 2 & 2 \\ 2 & 1 & -2 \\ a & 2 & b\end{array}\right] $ is an orthogonal matrix, thenA$ a=-2, b=-1 $B$ a=2, b=1 $C$ a=2, b=-1 $D$ a=-2, b=1 $Check AnswerClear SelectionReveal AnswerShow Explanation
