BitsatCircleBITSAT 2024MCQ+3 / -12024The locus of the mid-point of a chord of the circle $ x^{2}+y^{2}=4 $, which subtends a right angle at the origin isA$ x+y=2 $B$ x^{2}+y^{2}=1 $C$ x^{2}+y^{2}=2 $D$ x+y=1 $Check AnswerClear SelectionReveal AnswerShow Explanation
