Hydrocarbons

The final product in following reaction $ Y $ is, $ \mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2} \xrightarrow[\text { (ii) } \mathrm{NaBH}_{4}]{\text { (i) }\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{Hg}, \mathrm{CH}_{3} \mathrm{OH}} Y $