16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T48c,{"@context":"https://schema.org","@type":"Quiz","name":"Bitsat 2024 D And F Block Elements PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/bitsat/questions/2024/chemistry/d-and-f-block-elements/m7puosdp","educationalLevel":"Entrance exam preparation","about":"Bitsat / Chemistry / D And F Block Elements","hasPart":{"@type":"Question","name":"Bitsat 2024 D And F Block Elements PYQ with Solution","text":"The spin only magnetic moment of \\mathrm{Fe}^{3+} ion (in BM) is approximately.","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"C"},"comment":{"@type":"Comment","text":"The spin-only magnetic moment of the \\mathrm{Fe}^{3+} ion is determined by its electronic configuration and the number of unpaired electrons. Electronic Configuration: The neutral iron atom (_{26} \\mathrm{Fe}) has the electronic configuration: [\\mathrm{Ar}] 3d^6 4s^2 When it forms a \\mathrm{Fe}^{3+} ion, it loses three electrons. The configuration becomes: [\\mathrm{Ar}] 3d^5 Number of Unpaired Electrons: In the \\mathrm{Fe}^{3+} ion, there are 5 electrons in the 3d subshell. All these electrons..."}}}18:T4ce,

The spin-only magnetic moment of the $ \mathrm{Fe}^{3+} $ ion is determined by its electronic configuration and the number of unpaired electrons.

Electronic Configuration:

The neutral iron atom ($_{26} \mathrm{Fe}$) has the electronic configuration:

$ [\mathrm{Ar}] 3d^6 4s^2 $

When it forms a $ \mathrm{Fe}^{3+} $ ion

D And F Block Elements

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