Bitsat
Complex Numbers
BITSAT 2020
MCQ+3 / -12020
The root of the equation \(2(1 + i){x^2} - 4(2 - i)x - 5 - 3i = 0\), where \(i = \sqrt { - 1}\), which has greater modulus, is
Bitsat
BITSAT 2020
The root of the equation \(2(1 + i){x^2} - 4(2 - i)x - 5 - 3i = 0\), where \(i = \sqrt { - 1}\), which has greater modulus, is