Probability

The probability distribution of a discrete random variable $X$ is given below

$$ \begin{array}{lllll} \hline X=x & -1 & 0 & 1 & 2 \\ \hline P(X=x) & \frac{1}{3} & \frac{1}{6} & \frac{1}{6} & \frac{1}{3} \\ \hline \end{array} $$

Then, the value of $6 \sum\left(x^2\right) P(X=x)-\operatorname{var}(X)=$