Ap Eapcet
Limits Continuity And Differentiability
AP EAPCET 2025 - 26th May Evening Shift
MCQ+1 / -02025
\(\mathop {\lim }\limits_{x \to \infty } \frac{(3-x)^{25}(6+x)^{35}}{(12+x)^{38}(9-x)^{22}}=\)
Ap Eapcet
AP EAPCET 2025 - 26th May Evening Shift
\(\mathop {\lim }\limits_{x \to \infty } \frac{(3-x)^{25}(6+x)^{35}}{(12+x)^{38}(9-x)^{22}}=\)