Ap Eapcet
Hyperbola
AP EAPCET 2025 - 21st May Morning Shift
MCQ+1 / -02025
If the equation of the hyperbola having $(8,3),(0,3)$ as foci and $\frac{4}{3}$ as eccentricity is $\frac{(x-\alpha)^2}{p}-\frac{(y-\beta)^2}{q}=1$, then $p+q=$
Ap Eapcet
AP EAPCET 2025 - 21st May Morning Shift
If the equation of the hyperbola having $(8,3),(0,3)$ as foci and $\frac{4}{3}$ as eccentricity is $\frac{(x-\alpha)^2}{p}-\frac{(y-\beta)^2}{q}=1$, then $p+q=$