Ap Eapcet
Binomial Theorem
AP EAPCET 2025 - 27th May Morning Shift
MCQ+1 / -02025
\(\frac{1}{81^n}-{ }^{2 n} C_1 \frac{10}{81^n}+{ }^{2 n} C_2 \frac{10^2}{81^n}-\ldots+\frac{10^{2 n}}{81^n}=\)
Ap Eapcet
AP EAPCET 2025 - 27th May Morning Shift
\(\frac{1}{81^n}-{ }^{2 n} C_1 \frac{10}{81^n}+{ }^{2 n} C_2 \frac{10^2}{81^n}-\ldots+\frac{10^{2 n}}{81^n}=\)