Ap Eapcet
Application Of Derivatives
AP EAPCET 2025 - 23rd May Morning Shift
MCQ+1 / -02025
If $\frac{1}{2} \leq \frac{x^2+x+a}{x^2-x+a} \leq 2 \forall x \in R$, then $a=$
Ap Eapcet
AP EAPCET 2025 - 23rd May Morning Shift
If $\frac{1}{2} \leq \frac{x^2+x+a}{x^2-x+a} \leq 2 \forall x \in R$, then $a=$