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Chemical Equilibrium

AP EAPCET 2025 - 21st May Morning Shift

MCQ+1 / -02025

At $293 \mathrm{~K}, \Delta_r G^{\circ}$ for the following reaction is $165.469 \mathrm{~kJ} \mathrm{~mol}^{-1}$.


\(\frac{3}{2} \mathrm{O}_2(\mathrm{~g}) \longrightarrow \mathrm{O}_3(\mathrm{~g})\)


What is the equilibrium constant for this reaction?


\(\left(R=83 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)\)

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