16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T508,{"@context":"https://schema.org","@type":"Quiz","name":"Ap Eapcet 2024 Work Energy And Power PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ap-eapcet/questions/2024/physics/work-energy-and-power/m8vbdt1r","educationalLevel":"Entrance exam preparation","about":"Ap Eapcet / Physics / Work Energy And Power","hasPart":{"@type":"Question","name":"Ap Eapcet 2024 Work Energy And Power PYQ with Solution","text":"A spring of spring constant 200 \\mathrm{~N}-\\mathrm{m}^{-1} is initially stretched by 10 cm from the unstretched position. The work to be done to stretch the spring further by another 10 cm is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"Given the spring constant k = 200 \\, \\mathrm{N/m} . Initial stretch x_1 = 10 \\, \\mathrm{cm} = 0.1 \\, \\mathrm{m} Total (final) stretch x_2 = 20 \\, \\mathrm{cm} = 0.2 \\, \\mathrm{m} To find the work done to further stretch the spring by 10 cm, we use the formula for work done on a spring: W = U_2 - U_1 Where: U_2 is the elastic potential energy at the final stretch U_1 is the elastic potential energy at the initial stretch The formula for elastic potential energy U stored in a spring is: U = \\frac{..."}}}18:T43d,

Given the spring constant $ k = 200 \, \mathrm{N/m} $.

Initial stretch $ x_1 = 10 \, \mathrm{cm} = 0.1 \, \mathrm{m} $

Total (final) stretch $ x_2 = 20 \, \mathrm{cm} = 0.2 \, \mathrm{m} $

To find the work done t

Work Energy And Power

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