16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T500,{"@context":"https://schema.org","@type":"Quiz","name":"Ap Eapcet 2024 Waves PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ap-eapcet/questions/2024/physics/waves/m8vbe18x","educationalLevel":"Entrance exam preparation","about":"Ap Eapcet / Physics / Waves","hasPart":{"@type":"Question","name":"Ap Eapcet 2024 Waves PYQ with Solution","text":"A car sounding a horn of frequency 1000 Hz passes a stationary observer. The ratio of frequen'ies of the horn noted by the observer before and after passing of the car is 11: 9. The speed of car is (speed of sound v=340 \\mathrm{~ms}^{-1} )","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"Let's define: f = 1000 \\, \\text{Hz} : the original frequency of the horn. v = 340 \\, \\text{m/s} : the speed of sound. v_c : the speed of the car. Apparent Frequency Formulas Approaching Observer: f_1 = f \\left( \\frac{v}{v - v_c} \\right) Receding from Observer: f_2 = f \\left( \\frac{v}{v + v_c} \\right) Frequency Ratio Equation Given \\frac{f_1}{f_2} = \\frac{11}{9} , we equate and solve: \\frac{f \\left( \\frac{v}{v - v_c} \\right) }{f \\left( \\frac{v}{v + v_c} \\right) } = \\frac{v + v_c}{v - v_c} = \\fra..."}}}18:T41e,

Let's define:

$ f = 1000 \, \text{Hz} $: the original frequency of the horn.

$ v = 340 \, \text{m/s} $: the speed of sound.

$ v_c $: the speed of the car.

Apparent Frequency Formulas

Approa

Waves

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