16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4e3,{"@context":"https://schema.org","@type":"Quiz","name":"Ap Eapcet 2024 Wave Optics PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ap-eapcet/questions/2024/physics/wave-optics/m9yad7g8","educationalLevel":"Entrance exam preparation","about":"Ap Eapcet / Physics / Wave Optics","hasPart":{"@type":"Question","name":"Ap Eapcet 2024 Wave Optics PYQ with Solution","text":"The angle between the axes of a polariser and an analyser is 45^{\\circ}. If the intensity of the unpolarised light incident on the polariser is I, then the intensity of light emerged from the analyser is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"D"},"comment":{"@type":"Comment","text":"Given: Intensity of unpolarized light, I Angle between the polarizer and analyser, \\theta = 45^{\\circ} Step-by-step Breakdown Initial Intensity after Polariser: When unpolarized light passes through a polarizer, its intensity is reduced by half. Therefore, the intensity of polarized light emerging from the polarizer is: I_0 = \\frac{I}{2} Intensity after Analyser using Malus's Law: According to Malus's law, the intensity I_{\\text{out}} of the light after passing through the analyser is given by:..."}}}18:T4c8,

Given:

Intensity of unpolarized light, $ I $

Angle between the polarizer and analyser, $ \theta = 45^{\circ} $

Step-by-step Breakdown

Initial Intensity after Polariser:

When unpolarized light passes through a pol

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