16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T54e,{"@context":"https://schema.org","@type":"Quiz","name":"Ap Eapcet 2024 Simple Harmonic Motion PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ap-eapcet/questions/2024/physics/simple-harmonic-motion/m9yadgpg","educationalLevel":"Entrance exam preparation","about":"Ap Eapcet / Physics / Simple Harmonic Motion","hasPart":{"@type":"Question","name":"Ap Eapcet 2024 Simple Harmonic Motion PYQ with Solution","text":"The relation between the force ( F in Newton) acting on a particle executing simple harmonic motion and the displacement of the particle ( y in metre) is 500 F+\\pi^2 y=0. If the mass of the particle is 2 g . The time period of oscillation of the particle is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"C"},"comment":{"@type":"Comment","text":"Given: Mass of the particle : m = 2 \\, \\text{g} = 2 \\times 10^{-3} \\, \\text{kg} Displacement-force relationship : 500F + \\pi^2 y = 0 From this equation, we can express the force F in terms of the displacement y : F = \\frac{-\\pi^2 y}{500} In simple harmonic motion (SHM), force is also given by: F = -ky By comparing the two force equations, we identify the spring constant k : k = \\frac{\\pi^2}{500} The angular frequency \\omega for SHM is determined by: \\omega = \\sqrt{\\frac{k}{m}} Substituting the..."}}}18:T427,

Given:

Mass of the particle: $ m = 2 \, \text{g} = 2 \times 10^{-3} \, \text{kg} $

Displacement-force relationship: $ 5

Simple Harmonic Motion

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