16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4ff,{"@context":"https://schema.org","@type":"Quiz","name":"Ap Eapcet 2024 Ray Optics PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ap-eapcet/questions/2024/physics/ray-optics/m9yadl23","educationalLevel":"Entrance exam preparation","about":"Ap Eapcet / Physics / Ray Optics","hasPart":{"@type":"Question","name":"Ap Eapcet 2024 Ray Optics PYQ with Solution","text":"When a convex lens is immersed in a liquid of refractive index equal to 80 \\% of the refractive index of the material of the lens. The focal length of the lens increases by 100 \\%. The refractive index of the liquid is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"Given: Let the refractive index of the lens be \\mu_L. The refractive index of the liquid is given by 0.8 \\mu_L. Let's assign: The focal length of the lens in air as f. The focal length in the liquid as f_{\\text{liquid}} = 2f. Using the Lens Maker's formula in air: \\frac{1}{f} = (\\mu_L - 1)\\left(\\frac{1}{R_1} - \\frac{1}{R_2}\\right) \\tag{i} For the lens immersed in the liquid, the formula modifies to: \\frac{1}{f_{\\text{liquid}}} = \\left(\\frac{\\mu_L}{\\mu_{\\text{liquid}}} - 1\\right)\\left(\\frac{1}{R..."}}}18:T4fe,

Given:

Let the refractive index of the lens be $\mu_L$.

The refractive index of the liquid is given by $0.8 \mu_L$.

Let's assign:

The focal length of the lens in air as $f$.

The focal length in th

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