16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T51e,{"@context":"https://schema.org","@type":"Quiz","name":"Ap Eapcet 2024 Laws Of Motion PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ap-eapcet/questions/2024/physics/laws-of-motion/m9s6vlme","educationalLevel":"Entrance exam preparation","about":"Ap Eapcet / Physics / Laws Of Motion","hasPart":{"@type":"Question","name":"Ap Eapcet 2024 Laws Of Motion PYQ with Solution","text":"A block of mass 5 kg is placed on a rough horizontal surface having coefficient of friction 0.5 . If a horizontal force of 60 N is acting on it, then the acceleration of the block is (Acceleration due ot gravity, g=10 \\mathrm{~ms}^{-2} )","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"To find the acceleration of the block, we start with the given values: Mass of the block, m = 5 \\, \\text{kg} Coefficient of friction, \\mu = 0.5 Horizontal force applied, F_H = 60 \\, \\text{N} Acceleration due to gravity, g = 10 \\, \\text{m/s}^2 First, calculate the frictional force ( F_f ) using the formula: F_f = \\mu \\times N = \\mu \\times m \\times g Substitute the values: F_f = 0.5 \\times 5 \\times 10 F_f = 25 \\, \\text{N} Now, compute the net force ( F_{\\text{net}} ) acting on the block by subtra..."}}}18:T418,

To find the acceleration of the block, we start with the given values:

Mass of the block, $ m = 5 \, \text{kg} $

Coefficient of friction, $ \mu = 0.5 $

Horizontal force applied, $ F_H = 60

Laws Of Motion

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