Ap EapcetTrigonometric Ratios And IdentitiesAP EAPCET 2024 - 18th May Morning ShiftMCQ+1 / -02024$\sin^2 16^\circ - \sin^2 76^\circ = $A0B1C$\frac{1}{2}$D$\frac{3}{4}$Check AnswerClear SelectionReveal AnswerShow Explanation