Ap EapcetSequences And SeriesAP EAPCET 2024 - 19th May Evening ShiftMCQ+1 / -02024\(1-\frac{2}{3}+\frac{2 \cdot 4}{3 \cdot 6}-\frac{2 \cdot 4 \cdot 6}{3 \cdot 6 \cdot 9}+\ldots \infty=\)A$\frac{3}{5}$B$\left(\frac{2}{5}\right)^{\frac{2}{3}}$C$\frac{2}{5}$D$\left(\frac{3}{5}\right)^{\frac{2}{3}}$Check AnswerClear SelectionReveal AnswerShow Explanation