Ap EapcetQuadratic EquationsAP EAPCET 2024 - 21th May Morning ShiftMCQ+1 / -02024Roots of the equation $a(b-c) x^2+b(c-a) x+c(a-b)=0$ areA$\frac{a(b-c)}{c(a-b)}, 1$B$\frac{b(c-a)}{c(a-b)}, 1$C$\frac{c(a-b)}{a(b-c)}, 1$D$\frac{c(a-b)}{b(c-a)}, 1$Check AnswerClear SelectionReveal AnswerShow Explanation
