Ap Eapcet
Properties Of Triangles
AP EAPCET 2024 - 20th May Morning Shift
MCQ+1 / -02024
Match the items of List I with those of List II (here, $\Delta$ denotes the area of $\triangle A B C$ )
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\(\text { Then, the correct match is }\)
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.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;}
.tg .tg-baqh{text-align:center;vertical-align:top}
.tg .tg-0lax{text-align:left;vertical-align:top}
| List I | List II | ||
|---|---|---|---|
| (A) | \( \sum \cot A \) | (i) | \( (a+b+c)^2 \frac{1}{4 \Delta} \) |
| (B) | \( \sum \cot \frac{A}{2} \) | (ii) | \( \left(a^2+b^2+c^2\right) \frac{1}{4 \Delta} \) |
| (C) | If $\tan A: \tan B: \tan C=1: 2: 3$, then $\sin A: \sin B: \sin C=$ | (iii) | \( 8: 6: 5 \) |
| (D) | $$ \begin{aligned} &\text { If } \cot \frac{A}{2}: \cot \frac{B}{2}: \cot \frac{C}{2}=3: 7: 9\\ &\text { then } a: b: c= \end{aligned} $$ | (iv) | \( 12: 5: 13 \) |
| (v) | \( \sqrt{5}: 2 \sqrt{2}: 3 \) | ||
| (vi) | \( 4 \Delta \) | ||
\(\text { Then, the correct match is }\)
