Ap Eapcet
Limits Continuity And Differentiability
AP EAPCET 2024 - 23th May Morning Shift
MCQ+1 / -02024
The function $f(x)=\left\{\begin{array}{cc}\frac{x-|x|}{x}, & x \neq 0 \\ 2, & x=0\end{array}\right.$
Ap Eapcet
AP EAPCET 2024 - 23th May Morning Shift