Ap EapcetLimits Continuity And DifferentiabilityAP EAPCET 2024 - 19th May Evening ShiftMCQ+1 / -02024\(\lim \limits_{x \rightarrow 3} \frac{x^3-27}{x^2-9}=\)A$\frac{3}{2}$B$\frac{9}{2}$C3D2Check AnswerClear SelectionReveal AnswerShow Explanation