Ap EapcetInverse Trigonometric FunctionsAP EAPCET 2024 - 22th May Evening ShiftMCQ+1 / -02024$\cot \left(\sum\limits_{n=1}^{50} \tan ^{-1}\left(\frac{1}{1+n+n^2}\right)\right)$ is equal toA$\frac{26}{25}$B$\frac{25}{26}$C$\frac{50}{51}$D$\frac{52}{51}$Check AnswerClear SelectionReveal AnswerShow Explanation