Ap EapcetIndefinite IntegrationAP EAPCET 2024 - 18th May Morning ShiftMCQ+1 / -02024$\int e^{2 x+3} \sin 6 x d x=$A$\frac{e^{2 x+3}}{40}(2 \sin (x x+6 \cos 6 x)+c$B$\frac{e^{2 v+3}}{40}(2 \cos 6 x+6 \sin 6 x)+c$C$\frac{e^{2 n+3}}{20}(\sin 6 x-3 \cos 6 x)+c$D$\frac{e^{2 n 3}}{20}(\cos 8 x-3 \sin 6 x)+c$Check AnswerClear SelectionReveal AnswerShow Explanation
