Ap EapcetDifferentiationAP EAPCET 2024 - 18th May Morning ShiftMCQ+1 / -02024If $y=\tan ^{-1}\left(\frac{2-3 \sin x}{3-2 \sin x}\right)$, then $\frac{d y}{d x}=$A$\frac{(3-2 \sin x)^2}{13 \sin ^2 x-24 \sin x+13}$B$\frac{-5 \cos x}{13 \sin ^2 x-24 \sin x+19}$C$\frac{5 \sin x}{13 \sin ^2 x-24 \sin x+13}$D$\frac{-5 \sin x}{13 \sin ^2 x-24 \sin x+13}$Check AnswerClear SelectionReveal AnswerShow Explanation
